University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises - Page 202: 3



Work Step by Step

$y=x^3-3(x^2+\pi^2)=x^3-3x^2-3\pi^2$ $y'=3x^2-2\times3x-0=3x^2-6x$
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