University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises: 3

Answer

$3x^2-6x$

Work Step by Step

$y=x^3-3(x^2+\pi^2)=x^3-3x^2-3\pi^2$ $y'=3x^2-2\times3x-0=3x^2-6x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.