University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises - Page 202: 37



Work Step by Step

given $y=(2x+1)\sqrt{((2x+1))}$ $y={(2x+1)^\frac{3}{2}}$ on differentiating both sides: $\frac{dy}{dx}=\frac{d{(2x+1)^\frac{3}{2}}}{dx}$ $\frac{dy}{dx}=\frac{3}{2}{(\sqrt{(2x+1})}{\frac{d(2x+1)}{dx}}$ $\frac{dy}{dx}={3}{(\sqrt{(2x+1})}$
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