University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises - Page 202: 50

Answer

$\frac{dy}{dt}=2\ln(9)\times 9^{(2t)}$

Work Step by Step

$y=9^{2t}=e^{2t\times\ln(9)}$ On differentiating both sides: $\frac{dy}{dt}=2\ln(9)\times e^{2t\times\ln(9)}$ $\frac{dy}{dt}=2\ln(9)\times 9^{(2t)}$
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