University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises - Page 202: 42

Answer

$\frac{dy}{dx}={2}e^{\sqrt{2}{x}}$

Work Step by Step

$y=\sqrt{2}e^{\sqrt{2}{x}}$ on differentiating both sides: $\frac{dy}{dx}=\frac{d(\sqrt{2}e^{\sqrt{2}{x}})}{dx}$ $\frac{dy}{dx}=\sqrt{2}e^{\sqrt{2}{x}}\frac{d(\sqrt{2}{x})}{dx}$ $\frac{dy}{dx}={2}e^{\sqrt{2}{x}}$
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