University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises - Page 202: 57



Work Step by Step

$y=\ln{(\cos^{-1}{x})}$ On differentiating both sides: $\frac{dy}{dx}=\frac{d(\ln{(\cos^{-1}{x}}))}{dx}$ $\frac{dy}{dx}=\frac{1}{\cos^{-1}{x}}\frac{d({(\cos^{-1}{x}}))}{dx}$ $\frac{dy}{dx}=\frac{-1}{(\cos^{-1}{x})(\sqrt{1-x^2})}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.