University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Practice Exercises - Page 111: 52



Work Step by Step

$$A=\lim_{t\to\infty}\ln\Big(1+\frac{1}{t}\Big)$$ $$A=\ln\Big(1+\lim_{t\to\infty}\frac{1}{t}\Big)$$ As $t\to\infty$, $1/t$ approaches $0$. Therefore, $$A=\ln(1+0)=\ln1=0$$
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