Answer
$$\lim_{t\to\infty}\ln\Big(1+\frac{1}{t}\Big)=0$$
Work Step by Step
$$A=\lim_{t\to\infty}\ln\Big(1+\frac{1}{t}\Big)$$
$$A=\ln\Big(1+\lim_{t\to\infty}\frac{1}{t}\Big)$$
As $t\to\infty$, $1/t$ approaches $0$. Therefore,
$$A=\ln(1+0)=\ln1=0$$
