Answer
$$\lim_{t\to3^+}\ln(t-3)=-\infty$$
Work Step by Step
$$A=\lim_{t\to3^+}\ln(t-3)$$
As $t\to3^+$, $t-3$ approaches $0$ from the right.
$\ln0$ is not defined, but as $t-3$ approaches $0^+$, $\ln(t-3)$ gets infinitely smaller and smaller, and approaches $-\infty$.
Therefore, $$A=-\infty$$
