Answer
$$\lim_{x\to\pi}\sin\Big(\frac{x}{2}+\sin x\Big)=1$$
Work Step by Step
$$A=\lim_{x\to\pi}\sin\Big(\frac{x}{2}+\sin x\Big)$$
$$A=\sin\Big(\frac{\pi}{2}+\sin\pi\Big)$$
$$A=\sin\Big(\frac{\pi}{2}+0\Big)$$
$$A=\sin\frac{\pi}{2}=1$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 2 - Practice Exercises - Page 111: 21
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