Answer
$$\lim_{t\to1}t^2\ln(2-\sqrt t)=0$$
Work Step by Step
$$A=\lim_{t\to1}t^2\ln(2-\sqrt t)$$
$$A=1^2\times\ln(2-\sqrt1)=\ln(2-1)=\ln1$$
$$A=0$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 2 - Practice Exercises - Page 111: 26
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