University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Practice Exercises - Page 111: 26


$$\lim_{t\to1}t^2\ln(2-\sqrt t)=0$$

Work Step by Step

$$A=\lim_{t\to1}t^2\ln(2-\sqrt t)$$ $$A=1^2\times\ln(2-\sqrt1)=\ln(2-1)=\ln1$$ $$A=0$$
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