Answer
$$\lim_{x\to0^+}g(x)=2$$
Work Step by Step
$$\lim_{x\to0^+}(4g(x))^{1/3}=2$$
$$(\lim_{x\to0^+}4g(x))^{1/3}=2$$
$$\lim_{x\to0^+}4g(x)=8$$
$$4\lim_{x\to0^+}g(x)=8$$
$$\lim_{x\to0^+}g(x)=2$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 2 - Practice Exercises - Page 111: 29
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