University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Practice Exercises - Page 111: 14



Work Step by Step

$$A=\lim_{x\to0}\frac{(x+h)^2-x^2}{h}$$ $$A=\frac{(0+h)^2-0^2}{h}$$ $$A=\frac{h^2}{h}=h$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.