University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Practice Exercises - Page 111: 22

Answer

$$\lim_{x\to\pi}\cos^2(x-\tan x)=1$$

Work Step by Step

$$A=\lim_{x\to\pi}\cos^2(x-\tan x)$$ $$A=\cos^2(\pi-\tan\pi)$$ $$A=\cos^2(\pi-0)$$ $$A=\cos^2\pi$$ $$A=(-1)^2=1$$
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