Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 7



Work Step by Step

Integrate with respect to x and plug in limits to evaluate: $=\frac{1}{3}x^3+\frac{2}{3}x^{3/2}$ with limits from 0 to 1 $=[\frac{1}{3}(1)^3+\frac{2}{3}(1)^{2/3}]-0=1$
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