Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 11

Answer

0

Work Step by Step

$=-cscθ$ with limits from $π/4$ to $3π/4$ $=-csc(3π/4)+csc(π/4)=\frac{-2}{\sqrt 2}+\frac{2}{\sqrt 2}=0$
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