Answer
$\frac{2\pi}{3}$
Work Step by Step
$\int^{\frac{1}{2}}_{0}\frac{4}{\sqrt{1-x^2}}dx$
=4$sin^{-1}x|^{\frac{1}{2}}_0$
=4$sin_{-1}(\frac{1}{2})-4sin^{-1}0$
=4($\frac{\pi}{6}-4(0)$)
=$\frac{2\pi}{3}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 31
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