Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 28



Work Step by Step

$\int^{\pi}_{0}\frac{1}{2}(\cos x+|\cos x|)dx$ =$\int^{\pi}_{0}\frac{1}{2}(\cos x+\cos x)dx$ =$\int^{\pi}_{\frac{\pi}{2}}\frac{1}{2}(\cos x+|\cos x|)dx$ =$\int^{\pi}_{0}(\cos x)dx$ =$[\sin x]_{0}^{\frac{\pi}{2}}$ =$\sin \frac{\pi}{2} -\sin 0$ =1
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