Answer
$47\frac{1}{16}$
Work Step by Step
Integrate with respect to x and plug in limits to evaluate:
$=x^3-x^4/16$ with limits from 1 to 4
$=4^3-4^4/16-1^3+1^4/16=64-16-1+1/16=47\frac{1}{16}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 5
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