Answer
16
Work Step by Step
$\int^{4}_{-4}dx$
=$\int^{0}_{-4}|x|dx+\int^{4}_{0}|x|dx$
=-$\int^{0}_{-4}x dx+\int^{4}_{0}xdx$
=$[-\frac{x^2}{2}]_{-4}^0+[\frac{x^2}{2}]_0^4$
=$(\frac{0^2}{2}+\frac{(-4)^2}{2})+(\frac{4^2}{2}-\frac{0^2}{2})$
=16
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 27
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