## Thomas' Calculus 13th Edition

$-1/3$
First, factor the inside of the integral: $\int x^2-3x$ with limits from 0 to 2 Then, integrate and simplify: $=1/3x^3-3/2x$ with limits from 0 to 2 $=1/3(2)^3-3/2(2)-0=8/3-3=-1/3$