Answer
$-1/3$
Work Step by Step
First, factor the inside of the integral:
$\int x^2-3x$ with limits from 0 to 2
Then, integrate and simplify:
$=1/3x^3-3/2x$ with limits from 0 to 2
$=1/3(2)^3-3/2(2)-0=8/3-3=-1/3$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 1
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