Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 3



Work Step by Step

$\int_{-2}^{2}\frac{3}{(x+3)^4}dx$ $=-\frac{1}{(x+3)^3}]^2_{-2}$ $(-\frac{1}{(5)^3}-(-\frac{1}{(1)^3}))$ $=1-\frac{1}{125}=\frac{124}{125}$
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