Answer
$$\frac{3}{2}\tan x - 1.3\cos x - \frac{1}{{3.2}}{e^x} + C$$
Work Step by Step
$$\eqalign{
& \int {\left( {\frac{{3{{\sec }^2}x}}{2} + 1.3\sin x - \frac{{{e^x}}}{{3.2}}} \right)} dx \cr
& {\text{Distribute the integrand}} \cr
& {\text{ = }}\int {\frac{{3{{\sec }^2}x}}{2}} dx + \int {1.3\sin x} dx - \int {\frac{{{e^x}}}{{3.2}}} dx \cr
& {\text{Use the property }}\int {kf\left( x \right)dx} = k\int {f\left( x \right)} dx \cr
& {\text{ = }}\frac{3}{2}\int {{{\sec }^2}x} dx + 1.3\int {\sin x} dx - \frac{1}{{3.2}}\int {{e^x}} dx \cr
& {\text{Integrate, using basic rules}} \cr
& = \frac{3}{2}\tan x + 1.3\left( { - \cos x} \right) - \frac{1}{{3.2}}{e^x} + C \cr
& = \frac{3}{2}\tan x - 1.3\cos x - \frac{1}{{3.2}}{e^x} + C \cr} $$
