Answer
$\dfrac{1}{1.1} \cos (-1.1 x-1) +C $
Work Step by Step
Our aim is to solve the integral $ \int \sin (-1.1 x-1) \ dx$
Use formula:$ \int \sin (ax+b) \ dx =\dfrac{-1}{a} \cos (ax+b)+C$
Let us consider that $a =-1.1$ and $b=--1$
Now, $ \int \sin (-1.1 x-1) \ dx =\dfrac{-1}{-1.1} \cos (-1.1 x-1) +C $
or, $= \dfrac{1}{1.1} \cos (-1.1 x-1) +C $
