Answer
$ -\cos x - 2 \sin x +C$
Work Step by Step
We need to simplify: $\int (\sin x -2 \cos x ) \ dx $
Separate the integrals.
$ \int (\sin x -2 \cos x ) \ dx=\int \sin x \ dx - \int 2 \cos x \ dx$
or, $\int \sin x \ dx - \int 2 \cos x \ dx= -\cos x - 2 \sin x +C$
