Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 16 - Section 16.3 - Integrals of Trigonometric Functions and Applications - Exercises - Page 1178: 46

Answer

$x^2 \sin x +2x \cos x -2 \sin x +C$

Work Step by Step

Our aim is to solve the integral $ \int x^2 \cos x \ dx$ Use integration by parts formula. $\int x^2 \cos x \ dx=x^2 \times \sin x -\int (\sin x) (2x) \ dx $ or, $=x^2 \sin x -[-2x \cos x +2 \int \cos x \ dx]$ or, $=x^2 \sin x +2x \cos x -2 \sin x +C$
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