Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 16 - Section 16.3 - Integrals of Trigonometric Functions and Applications - Exercises - Page 1178: 3

Answer

$2 \sin x \ dx +4. 3 \cos x- 9.33 x +C$

Work Step by Step

We need to simplify: $\int (2 \cos x - 4. 3 \sin x -9.33) \ dx $ Separate the integrals. $ \int (2 \cos x - 4. 3 \sin x -9.33) \ dx=\int 2 \cos x \ dx - \int 4. 3 \sin x dx-\int 9.33 \ dx$ or, $= 2 \sin x \ dx +4. 3 \cos x- 9.33 x +C$
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