Answer
$\ln 2$
Work Step by Step
Our aim is to solve the integral $\int_{0}^{\pi/3 } \tan x \ dx$
Now, $\int_{0}^{\pi/3 } \tan x \ dx=[-\ln |\cos x|]_{0}^{\pi/3 }$
or, $=-\ln |\cos (\pi/3)|--\ln |\cos (0)|$
or, $= -\ln |\dfrac{1}{2}|-\ln |1|$
or, $=\ln 2$
