Answer
$-1$
Work Step by Step
Our aim is to solve the integral $\int_{\pi/2}^{\pi} \cos x \ dx$
Now, $\int_{\pi/2}^{\pi} \cos x \ dx=[\sin x]_{\pi/2}^{\pi}$
or, $=\sin (\pi) -\sin (\pi/2)$
or, $= 0-1$
or, $=-1$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 16 - Section 16.3 - Integrals of Trigonometric Functions and Applications - Exercises - Page 1178: 22
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