Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 9

Answer

$18\pi$

Work Step by Step

If y=0, then x=1, x=34, so that a=1, b=4. The volume is $V=\int^{4}_{1}\pi(\sqrt 2x +1)^{2}dx=\pi[\frac{(2x+1)^{2}}{4}]^{4}_{1}=18\pi$
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