Answer
$4\pi \ln4 $
Work Step by Step
If y=0, then x=-1, x=2, so that a=-1, b=2. The volume is $V=\int^{2}_{-1}\pi(\frac{2}{\sqrt x +2})^{2}dx=4\pi[\ln |x+2|]|^{2}_{-1} =4\pi \ln4 $
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 14
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