## Calculus with Applications (10th Edition)

$2\pi(e^{2}-e^{-4})$
If y=0, then x=-2 and x=1, meaning that a=-2, b=1. The volume is: $V=\int^{1}_{-2}\pi(2e^{x})^{2}dx=4\pi[\frac{e^{2x}}{2}]|^{1}_{-2}=2\pi(e^{2}-e^{-4})$