Answer
$2\pi(e^{2}-e^{-4})$
Work Step by Step
If y=0, then x=-2 and x=1, meaning that a=-2, b=1. The volume is: $V=\int^{1}_{-2}\pi(2e^{x})^{2}dx=4\pi[\frac{e^{2x}}{2}]|^{1}_{-2}=2\pi(e^{2}-e^{-4})$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 12
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