Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 12



Work Step by Step

If y=0, then x=-2 and x=1, meaning that a=-2, b=1. The volume is: $V=\int^{1}_{-2}\pi(2e^{x})^{2}dx=4\pi[\frac{e^{2x}}{2}]|^{1}_{-2}=2\pi(e^{2}-e^{-4})$
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