Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 8

Answer

$14\pi$

Work Step by Step

If y=0, then x=1, x=3, so that a=1, b=3. The volume is $V=\int^{3}_{1}\pi(\sqrt x +5)^{2}dx=\pi[\frac{(x+5)^{2}}{2}]^{3}_{1}=14\pi$
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