Answer
$(e^{4}-1)\pi/2$
Work Step by Step
If y=0, then x=0, x=2, so that a=0, b=2. The volume is
$V=\int^{2}_{0}\pi(e^{x})^{2}dx=\pi[e^{2x}]/2|^{2}_{0}=(e^{4}-1)\pi/2$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 11
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