Answer
$4\pi \ln3$
Work Step by Step
If y=0, then x=1, and x=3, meaning that a=1 and b=3. The volume is $V=\int^{3}_{1}\pi(\frac{2}{\sqrt x})^{2}dx=4\pi[\ln |x|]|^{3}_{1} =4\pi (\ln3 -\ln1) = 4\pi \ln3$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 13
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