## Calculus with Applications (10th Edition)

$\frac{364\pi}{3}$
Use the formula given above for the volume, with a= 0, b=4 and f(x) =2x+1 $V=\int^{4}_{0} \pi (2x+1)^{2}dx=\int^{4}_{0}\pi(4x^{2} +4x+1)dx=\pi [\frac{4x^{3}}{3}+2x^{2}+x]|^{4}_{0}=\frac{364\pi}{3}$