Answer
$\frac{15\pi}{2}$
Work Step by Step
Use the formula given above for the volume, with a=1, b=4 and $f(x) =\sqrt x$
$V=\int^{4}_{1} \pi (\sqrt x)^{2}dx=\pi [\frac{(x^{2})}{2}]|^{4}_{1}=\frac{15\pi}{2}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 7
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