Answer
$\frac{9\pi}{1}$
Work Step by Step
Use the formula given above for the volume, with a= 0, b=3 and f(x) =x
$V=\int^{3}_{0} \pi (x)^{2}dx=\pi (\frac{x^{3}}{3})|^{3}_{0}=\frac{9\pi}{1}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 1
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