## Calculus with Applications (10th Edition)

$72\pi$
Use the formula given above for the volume, with a= 4, b=10 and f(x)=x-4 $V=\int^{10}_{4} \pi (x -4)^{2}dx=\int^{10}_{4}\pi(x^{2} -8x+16)dx=\pi [\frac{x^{3}}{3}-4x^{2}+16x]|^{10}_{4}=72\pi$