Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 4

Answer

$72\pi$

Work Step by Step

Use the formula given above for the volume, with a= 4, b=10 and f(x)=x-4 $V=\int^{10}_{4} \pi (x -4)^{2}dx=\int^{10}_{4}\pi(x^{2} -8x+16)dx=\pi [\frac{x^{3}}{3}-4x^{2}+16x]|^{10}_{4}=72\pi$
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