Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 439: 15

Answer

$=\frac{3124\pi}{5} $

Work Step by Step

If y=0, then x=1, x=5, so that a=1, b=5. The volume is $V=\int^{5}_{1}\pi(x^{2})^{2}dx=\pi\frac{x^{5}}{5}|^{5}_{1} =\frac{3124\pi}{5} $
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