Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - Review Exercises - Page 393: 8

Answer

$f'(x) = \frac{6x+2}{x(3x + 2)}$

Work Step by Step

$f(x) = \ln(3x^{2} +2x)$ $f'(x) = \frac{1}{(3x^{2} +2x)}(6x + 2)$ $f'(x) = \frac{6x+2}{3x^{2} +2x}$ $f'(x) = \frac{6x+2}{x(3x + 2)}$
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