Answer
$f'(x) = \frac{6x+2}{x(3x + 2)}$
Work Step by Step
$f(x) = \ln(3x^{2} +2x)$
$f'(x) = \frac{1}{(3x^{2} +2x)}(6x + 2)$
$f'(x) = \frac{6x+2}{3x^{2} +2x}$
$f'(x) = \frac{6x+2}{x(3x + 2)}$
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