Answer
$f'(x) = \frac{3[\ln(2x)]^{2}}{x}$
Work Step by Step
$f(x) = [\ln(2x)]^{3}$
$f'(x) = 3[\ln(2x)]^{2}(\frac{1}{2x})(2)$
$= 3[\ln(2x)]^{2}(\frac{2}{2x})$
$= 3[\ln(2x)]^{2}(\frac{1}{x})$
$f'(x) = \frac{3[\ln(2x)]^{2}}{x}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - Review Exercises - Page 393: 10
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