Answer
$y = 6x - 4$
Work Step by Step
1. Find the derivative
$y = 2x^{2} + ln(x^{2})$
$y' = 4x + \frac{1}{x^{2}}(2x)$
$y' = 4x + \frac{2x}{x^{2}}$
$y' = 4x + \frac{2}{x}$
2. Substitute the $x$ coordinate to find the slope of the tangent
$m = 4(1) + \frac{2}{1}$
$m = 4 + 2$
$m = 6$
3. Substitute the slope of the tangent into the equation of the line
$y = mx + b$
$2 = 6(1) + b$
$2 = 6 + b$
$-4 = b$
$b = -4$
$y = 6x - 4$
