Answer
$g'(t) = te^{t}(2+t)$
Work Step by Step
$g(t) = t^{2}e^{t}$
$g'(t) = 2te^{t} + t^{2}e^{t}$
$g'(t) = te^{t}(2+t)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - Review Exercises - Page 393: 37
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