Answer
$= \frac{1}{3}\ln|x^{3}+1| + c$
Work Step by Step
Let $u = x^{3} + 1$
$u' = 3x^{2}$
$\frac{du}{dx} = 3x^{2}$
$\frac{du}{3} = x^{2}$
$\frac{1}{3}\int du(u)^{-1}dx$
$= \frac{1}{3}\ln|u| + c$
$= \frac{1}{3}\ln|x^{3}+1| + c$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - Review Exercises - Page 393: 16
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
