Answer
$= - \ln |1+\cos x| + c$
Work Step by Step
$\int \frac{sin(x)}{1+ cos(x)} dx$
Let $u = 1 + cosx$
$u' = -sinx$
$\frac{du}{dx} = -\sin x$
$\frac{du}{-1} = \sin xdx$
$-\int du(u)^{-1}dx$
$= - \ln |u|+c$
$= - \ln |1+\cos x| + c$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - Review Exercises - Page 393: 17
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
