Answer
$= \ln (\frac{3\sqrt[3] {4-x^{2}}}{x})$
Work Step by Step
$= \ln 3 + \frac{1}{3} \ln (4-x^{2}) - \ln x$
$= \ln 3 - \ln x + \frac{1}{3} \ln (4-x^{2})$
$= \ln \frac{3}{x} +\frac{1}{3} \ln (4-x^{2})$
$= \ln \frac{3}{x} + \ln (4-x^{2})^{\frac{1}{3}}$
$=\ln \frac{3(4-x^{2})^{\frac{1}{3}}}{x}$
$= \ln (\frac{3\sqrt[3] {4-x^{2}}}{x})$