Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - Review Exercises - Page 393: 5

Answer

$= \ln (\frac{3\sqrt[3] {4-x^{2}}}{x})$

Work Step by Step

$= \ln 3 + \frac{1}{3} \ln (4-x^{2}) - \ln x$ $= \ln 3 - \ln x + \frac{1}{3} \ln (4-x^{2})$ $= \ln \frac{3}{x} +\frac{1}{3} \ln (4-x^{2})$ $= \ln \frac{3}{x} + \ln (4-x^{2})^{\frac{1}{3}}$ $=\ln \frac{3(4-x^{2})^{\frac{1}{3}}}{x}$ $= \ln (\frac{3\sqrt[3] {4-x^{2}}}{x})$
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