Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - Review Exercises - Page 393: 3

$= \frac{1}{5}(\ln(4x^{2} - 1) - \ln(4x^{2} + 1))$

$= \ln\sqrt[5] {(\frac{4x^{2}-1}{4x^{2}+1})}$ $= \ln(\frac{4x^{2}-1}{4x^{2}+1})^{\frac{1}{5}}$ $= \frac{1}{5}\ln (\frac{4x^{2}-1}{4x^{2}+1})$ $= \frac{1}{5}(\ln(4x^{2} - 1) - \ln(4x^{2} + 1))$