Answer
$y' = \frac{-6}{x(x-6)}$
Work Step by Step
$y = \ln(\frac{4x}{x-6})$
$y = \ln(4x) - \ln(x-6)$
$y' = (\frac{1}{4x})(4)-(\frac{1}{x-6})(1)$
$y' = \frac{4}{4x} - \frac{1}{x-6}$
$y' = \frac{1}{x} - \frac{1}{x-6}$
$y' = \frac{x-6-x}{x(x-6)}$
$y' = \frac{-6}{x(x-6)}$