Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - Review Exercises - Page 393: 12

Answer

$y' = \frac{-6}{x(x-6)}$

Work Step by Step

$y = \ln(\frac{4x}{x-6})$ $y = \ln(4x) - \ln(x-6)$ $y' = (\frac{1}{4x})(4)-(\frac{1}{x-6})(1)$ $y' = \frac{4}{4x} - \frac{1}{x-6}$ $y' = \frac{1}{x} - \frac{1}{x-6}$ $y' = \frac{x-6-x}{x(x-6)}$ $y' = \frac{-6}{x(x-6)}$
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