Answer
$\frac{dy}{dx} = \frac{(3-2x)^{\frac{1}{3}}(\frac{4}{3}x^2-6x)}{x^4} $
Work Step by Step
Applying power rule and chain rule:
$\frac{dy}{dx} = \frac{-\frac{8}{3}(3-2x)^{\frac{1}{3}}*x^2 - (2x)*(3-2x)^{\frac{4}{3}}}{x^4} = \frac{(3-2x)^{\frac{1}{3}}(-\frac{8}{3}x^2-2x(3-2x))}{x^4} = \frac{(3-2x)^{\frac{1}{3}}(\frac{4}{3}x^2-6x)}{x^4} $
