Answer
$\frac{dy}{dx}=\frac{(2x+1)}{3(x^2+x)^{\frac{2}{3}}}$
Work Step by Step
Applying power rule and chain rule:
$\frac{dy}{dx} = \frac{1}{3}(x^2+x)^{-\frac{2}{3}} * (2x+1)\\ = \frac{(2x+1)}{3(x^2+x)^{\frac{2}{3}}}$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 2 - The Derivative - Chapter 2 Review Exercises - Page 185: 43
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