Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.4 The Product And Quotient Rules - Exercises Set 2.4 - Page 147: 25

Answer

$f'(x)=-3[x+csc(x^{3}+3)]^{-4}\cdot [(1-3x^{2})csc(x^{3}+3)cot(x^{3}+3)$

Work Step by Step

Use chain rule $f'(x)=-3[x+csc(x^{3}+3)]^{-4}.\frac{d}{dx}[x+csc(x^{3}+3)$ $=-3[x+csc(x^{3}+3)]^{-4}.[1+(-csc(x^{3}+3)cot(x^{3}+3))(3x^{-2})$ $=-3[x+csc(x^{3}+3)]^{-4}.[(1-3x^{2})csc(x^{3}+3)cot(x^{3}+3)$
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